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(1/3)^x+1=9
We move all terms to the left:
(1/3)^x+1-(9)=0
Domain of the equation: 3)^x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+1/3)^x+1-9=0
We add all the numbers together, and all the variables
(+1/3)^x-8=0
We multiply all the terms by the denominator
(+1-8*3)^x=0
We add all the numbers together, and all the variables
(-23)^x=0
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